3x^2+7=x^2+1

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Solution for 3x^2+7=x^2+1 equation: 



3x^2+7=x^2+1

We move all terms to the left:

3x^2+7-(x^2+1)=0

We get rid of parentheses

3x^2-x^2-1+7=0

We add all the numbers together, and all the variables

2x^2+6=0

a = 2; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·2·6
Δ = -48
Delta is less than zero, so there is no solution for the equation

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